Integrand size = 32, antiderivative size = 258 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {2 b d^2 g n^2 x}{e^2}-\frac {b d g n^2 (d+e x)^2}{2 e^3}+\frac {2 b g n^2 (d+e x)^3}{27 e^3}-\frac {b d^3 g n^2 \log ^2(d+e x)}{3 e^3}+\frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3} \]
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Time = 0.21 (sec) , antiderivative size = 258, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.219, Rules used = {2483, 2458, 45, 2372, 12, 14, 2338} \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {d^3 n \log (d+e x) \left (a g+2 b g \log \left (c (d+e x)^n\right )+b f\right )}{3 e^3}-\frac {d^2 n (d+e x) \left (a g+2 b g \log \left (c (d+e x)^n\right )+b f\right )}{e^3}+\frac {d n (d+e x)^2 \left (a g+2 b g \log \left (c (d+e x)^n\right )+b f\right )}{2 e^3}-\frac {n (d+e x)^3 \left (a g+2 b g \log \left (c (d+e x)^n\right )+b f\right )}{9 e^3}+\frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (g \log \left (c (d+e x)^n\right )+f\right )-\frac {b d^3 g n^2 \log ^2(d+e x)}{3 e^3}+\frac {2 b d^2 g n^2 x}{e^2}-\frac {b d g n^2 (d+e x)^2}{2 e^3}+\frac {2 b g n^2 (d+e x)^3}{27 e^3} \]
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Rule 12
Rule 14
Rule 45
Rule 2338
Rule 2372
Rule 2458
Rule 2483
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {1}{3} (e n) \int \frac {x^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{d+e x} \, dx \\ & = \frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {1}{3} n \text {Subst}\left (\int \frac {\left (-\frac {d}{e}+\frac {x}{e}\right )^3 \left (b f+a g+2 b g \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right ) \\ & = \frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3}+\frac {1}{3} \left (2 b g n^2\right ) \text {Subst}\left (\int \frac {18 d^2 x-9 d x^2+2 x^3-6 d^3 \log (x)}{6 e^3 x} \, dx,x,d+e x\right ) \\ & = \frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3}+\frac {\left (b g n^2\right ) \text {Subst}\left (\int \frac {18 d^2 x-9 d x^2+2 x^3-6 d^3 \log (x)}{x} \, dx,x,d+e x\right )}{9 e^3} \\ & = \frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3}+\frac {\left (b g n^2\right ) \text {Subst}\left (\int \left (18 d^2-9 d x+2 x^2-\frac {6 d^3 \log (x)}{x}\right ) \, dx,x,d+e x\right )}{9 e^3} \\ & = \frac {2 b d^2 g n^2 x}{e^2}-\frac {b d g n^2 (d+e x)^2}{2 e^3}+\frac {2 b g n^2 (d+e x)^3}{27 e^3}+\frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3}-\frac {\left (2 b d^3 g n^2\right ) \text {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,d+e x\right )}{3 e^3} \\ & = \frac {2 b d^2 g n^2 x}{e^2}-\frac {b d g n^2 (d+e x)^2}{2 e^3}+\frac {2 b g n^2 (d+e x)^3}{27 e^3}-\frac {b d^3 g n^2 \log ^2(d+e x)}{3 e^3}+\frac {1}{3} x^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right )-\frac {d^2 n (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac {d n (d+e x)^2 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{2 e^3}-\frac {n (d+e x)^3 \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{9 e^3}+\frac {d^3 n \log (d+e x) \left (b f+a g+2 b g \log \left (c (d+e x)^n\right )\right )}{3 e^3} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 205, normalized size of antiderivative = 0.79 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {e x \left (3 a \left (-6 d^2 g n+3 d e g n x+2 e^2 (3 f-g n) x^2\right )+b n \left (d^2 (-18 f+66 g n)+3 d e (3 f-5 g n) x+2 e^2 (-3 f+2 g n) x^2\right )\right )+18 d^3 (b f+a g) n \log (d+e x)-6 \left (-3 a e^3 g x^3+b \left (11 d^3 g n+6 d^2 e g n x-3 d e^2 g n x^2+e^3 (-3 f+2 g n) x^3\right )\right ) \log \left (c (d+e x)^n\right )+18 b g \left (d^3+e^3 x^3\right ) \log ^2\left (c (d+e x)^n\right )}{54 e^3} \]
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Time = 0.66 (sec) , antiderivative size = 354, normalized size of antiderivative = 1.37
method | result | size |
parallelrisch | \(\frac {18 a \,e^{3} f \,x^{3}-66 b \,d^{3} g \,n^{2}-12 x^{3} \ln \left (c \left (e x +d \right )^{n}\right ) b \,e^{3} g n -102 \ln \left (e x +d \right ) b \,d^{3} g \,n^{2}+18 \ln \left (e x +d \right ) a \,d^{3} g n +18 \ln \left (e x +d \right ) b \,d^{3} f n -15 b d \,e^{2} g \,n^{2} x^{2}+66 b \,d^{2} e g \,n^{2} x +18 a \,d^{3} g n +18 b \,d^{3} f n +4 b \,e^{3} g \,n^{2} x^{3}-6 n a \,e^{3} g \,x^{3}-6 n b \,e^{3} f \,x^{3}-36 x \ln \left (c \left (e x +d \right )^{n}\right ) b \,d^{2} e g n +18 x^{2} \ln \left (c \left (e x +d \right )^{n}\right ) b d \,e^{2} g n +18 x^{3} \ln \left (c \left (e x +d \right )^{n}\right )^{2} b \,e^{3} g +18 x^{3} \ln \left (c \left (e x +d \right )^{n}\right ) a \,e^{3} g +18 x^{3} \ln \left (c \left (e x +d \right )^{n}\right ) b \,e^{3} f +36 \ln \left (c \left (e x +d \right )^{n}\right ) b \,d^{3} g n +18 \ln \left (c \left (e x +d \right )^{n}\right )^{2} b \,d^{3} g -18 a \,d^{2} e g n x -18 b \,d^{2} e f n x +9 a d \,e^{2} g n \,x^{2}+9 b d \,e^{2} f n \,x^{2}}{54 e^{3}}\) | \(354\) |
risch | \(\text {Expression too large to display}\) | \(1785\) |
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Time = 0.29 (sec) , antiderivative size = 329, normalized size of antiderivative = 1.28 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {18 \, b e^{3} g x^{3} \log \left (c\right )^{2} + 2 \, {\left (2 \, b e^{3} g n^{2} + 9 \, a e^{3} f - 3 \, {\left (b e^{3} f + a e^{3} g\right )} n\right )} x^{3} - 3 \, {\left (5 \, b d e^{2} g n^{2} - 3 \, {\left (b d e^{2} f + a d e^{2} g\right )} n\right )} x^{2} + 18 \, {\left (b e^{3} g n^{2} x^{3} + b d^{3} g n^{2}\right )} \log \left (e x + d\right )^{2} + 6 \, {\left (11 \, b d^{2} e g n^{2} - 3 \, {\left (b d^{2} e f + a d^{2} e g\right )} n\right )} x + 6 \, {\left (3 \, b d e^{2} g n^{2} x^{2} - 6 \, b d^{2} e g n^{2} x - 11 \, b d^{3} g n^{2} - {\left (2 \, b e^{3} g n^{2} - 3 \, {\left (b e^{3} f + a e^{3} g\right )} n\right )} x^{3} + 3 \, {\left (b d^{3} f + a d^{3} g\right )} n + 6 \, {\left (b e^{3} g n x^{3} + b d^{3} g n\right )} \log \left (c\right )\right )} \log \left (e x + d\right ) + 6 \, {\left (3 \, b d e^{2} g n x^{2} - 6 \, b d^{2} e g n x - {\left (2 \, b e^{3} g n - 3 \, b e^{3} f - 3 \, a e^{3} g\right )} x^{3}\right )} \log \left (c\right )}{54 \, e^{3}} \]
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Time = 1.17 (sec) , antiderivative size = 384, normalized size of antiderivative = 1.49 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\begin {cases} \frac {a d^{3} g \log {\left (c \left (d + e x\right )^{n} \right )}}{3 e^{3}} - \frac {a d^{2} g n x}{3 e^{2}} + \frac {a d g n x^{2}}{6 e} + \frac {a f x^{3}}{3} - \frac {a g n x^{3}}{9} + \frac {a g x^{3} \log {\left (c \left (d + e x\right )^{n} \right )}}{3} + \frac {b d^{3} f \log {\left (c \left (d + e x\right )^{n} \right )}}{3 e^{3}} - \frac {11 b d^{3} g n \log {\left (c \left (d + e x\right )^{n} \right )}}{9 e^{3}} + \frac {b d^{3} g \log {\left (c \left (d + e x\right )^{n} \right )}^{2}}{3 e^{3}} - \frac {b d^{2} f n x}{3 e^{2}} + \frac {11 b d^{2} g n^{2} x}{9 e^{2}} - \frac {2 b d^{2} g n x \log {\left (c \left (d + e x\right )^{n} \right )}}{3 e^{2}} + \frac {b d f n x^{2}}{6 e} - \frac {5 b d g n^{2} x^{2}}{18 e} + \frac {b d g n x^{2} \log {\left (c \left (d + e x\right )^{n} \right )}}{3 e} - \frac {b f n x^{3}}{9} + \frac {b f x^{3} \log {\left (c \left (d + e x\right )^{n} \right )}}{3} + \frac {2 b g n^{2} x^{3}}{27} - \frac {2 b g n x^{3} \log {\left (c \left (d + e x\right )^{n} \right )}}{9} + \frac {b g x^{3} \log {\left (c \left (d + e x\right )^{n} \right )}^{2}}{3} & \text {for}\: e \neq 0 \\\frac {x^{3} \left (a + b \log {\left (c d^{n} \right )}\right ) \left (f + g \log {\left (c d^{n} \right )}\right )}{3} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 274, normalized size of antiderivative = 1.06 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {1}{3} \, b g x^{3} \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + \frac {1}{3} \, b f x^{3} \log \left ({\left (e x + d\right )}^{n} c\right ) + \frac {1}{3} \, a g x^{3} \log \left ({\left (e x + d\right )}^{n} c\right ) + \frac {1}{3} \, a f x^{3} + \frac {1}{18} \, b e f n {\left (\frac {6 \, d^{3} \log \left (e x + d\right )}{e^{4}} - \frac {2 \, e^{2} x^{3} - 3 \, d e x^{2} + 6 \, d^{2} x}{e^{3}}\right )} + \frac {1}{18} \, a e g n {\left (\frac {6 \, d^{3} \log \left (e x + d\right )}{e^{4}} - \frac {2 \, e^{2} x^{3} - 3 \, d e x^{2} + 6 \, d^{2} x}{e^{3}}\right )} + \frac {1}{54} \, {\left (6 \, e n {\left (\frac {6 \, d^{3} \log \left (e x + d\right )}{e^{4}} - \frac {2 \, e^{2} x^{3} - 3 \, d e x^{2} + 6 \, d^{2} x}{e^{3}}\right )} \log \left ({\left (e x + d\right )}^{n} c\right ) + \frac {{\left (4 \, e^{3} x^{3} - 15 \, d e^{2} x^{2} - 18 \, d^{3} \log \left (e x + d\right )^{2} + 66 \, d^{2} e x - 66 \, d^{3} \log \left (e x + d\right )\right )} n^{2}}{e^{3}}\right )} b g \]
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Leaf count of result is larger than twice the leaf count of optimal. 741 vs. \(2 (244) = 488\).
Time = 0.31 (sec) , antiderivative size = 741, normalized size of antiderivative = 2.87 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\frac {{\left (e x + d\right )}^{3} b g n^{2} \log \left (e x + d\right )^{2}}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} b d g n^{2} \log \left (e x + d\right )^{2}}{e^{3}} + \frac {{\left (e x + d\right )} b d^{2} g n^{2} \log \left (e x + d\right )^{2}}{e^{3}} - \frac {2 \, {\left (e x + d\right )}^{3} b g n^{2} \log \left (e x + d\right )}{9 \, e^{3}} + \frac {{\left (e x + d\right )}^{2} b d g n^{2} \log \left (e x + d\right )}{e^{3}} - \frac {2 \, {\left (e x + d\right )} b d^{2} g n^{2} \log \left (e x + d\right )}{e^{3}} + \frac {2 \, {\left (e x + d\right )}^{3} b g n \log \left (e x + d\right ) \log \left (c\right )}{3 \, e^{3}} - \frac {2 \, {\left (e x + d\right )}^{2} b d g n \log \left (e x + d\right ) \log \left (c\right )}{e^{3}} + \frac {2 \, {\left (e x + d\right )} b d^{2} g n \log \left (e x + d\right ) \log \left (c\right )}{e^{3}} + \frac {2 \, {\left (e x + d\right )}^{3} b g n^{2}}{27 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} b d g n^{2}}{2 \, e^{3}} + \frac {2 \, {\left (e x + d\right )} b d^{2} g n^{2}}{e^{3}} + \frac {{\left (e x + d\right )}^{3} b f n \log \left (e x + d\right )}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} b d f n \log \left (e x + d\right )}{e^{3}} + \frac {{\left (e x + d\right )} b d^{2} f n \log \left (e x + d\right )}{e^{3}} + \frac {{\left (e x + d\right )}^{3} a g n \log \left (e x + d\right )}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} a d g n \log \left (e x + d\right )}{e^{3}} + \frac {{\left (e x + d\right )} a d^{2} g n \log \left (e x + d\right )}{e^{3}} - \frac {2 \, {\left (e x + d\right )}^{3} b g n \log \left (c\right )}{9 \, e^{3}} + \frac {{\left (e x + d\right )}^{2} b d g n \log \left (c\right )}{e^{3}} - \frac {2 \, {\left (e x + d\right )} b d^{2} g n \log \left (c\right )}{e^{3}} + \frac {{\left (e x + d\right )}^{3} b g \log \left (c\right )^{2}}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} b d g \log \left (c\right )^{2}}{e^{3}} + \frac {{\left (e x + d\right )} b d^{2} g \log \left (c\right )^{2}}{e^{3}} - \frac {{\left (e x + d\right )}^{3} b f n}{9 \, e^{3}} + \frac {{\left (e x + d\right )}^{2} b d f n}{2 \, e^{3}} - \frac {{\left (e x + d\right )} b d^{2} f n}{e^{3}} - \frac {{\left (e x + d\right )}^{3} a g n}{9 \, e^{3}} + \frac {{\left (e x + d\right )}^{2} a d g n}{2 \, e^{3}} - \frac {{\left (e x + d\right )} a d^{2} g n}{e^{3}} + \frac {{\left (e x + d\right )}^{3} b f \log \left (c\right )}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} b d f \log \left (c\right )}{e^{3}} + \frac {{\left (e x + d\right )} b d^{2} f \log \left (c\right )}{e^{3}} + \frac {{\left (e x + d\right )}^{3} a g \log \left (c\right )}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} a d g \log \left (c\right )}{e^{3}} + \frac {{\left (e x + d\right )} a d^{2} g \log \left (c\right )}{e^{3}} + \frac {{\left (e x + d\right )}^{3} a f}{3 \, e^{3}} - \frac {{\left (e x + d\right )}^{2} a d f}{e^{3}} + \frac {{\left (e x + d\right )} a d^{2} f}{e^{3}} \]
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Time = 1.47 (sec) , antiderivative size = 323, normalized size of antiderivative = 1.25 \[ \int x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (c (d+e x)^n\right )\right ) \, dx=\ln \left (c\,{\left (d+e\,x\right )}^n\right )\,\left (\frac {x^3\,\left (a\,g+b\,f-\frac {2\,b\,g\,n}{3}\right )}{3}+\frac {x^2\,\left (\frac {3\,d\,\left (a\,g+b\,f\right )}{2\,e}-\frac {d\,\left (9\,a\,g+9\,b\,f-6\,b\,g\,n\right )}{6\,e}\right )}{3}-\frac {d\,x\,\left (\frac {9\,d\,\left (a\,g+b\,f\right )}{e}-\frac {d\,\left (9\,a\,g+9\,b\,f-6\,b\,g\,n\right )}{e}\right )}{9\,e}\right )+x^2\,\left (\frac {d\,\left (3\,a\,f-b\,g\,n^2\right )}{6\,e}-\frac {d\,\left (a\,f-\frac {a\,g\,n}{3}-\frac {b\,f\,n}{3}+\frac {2\,b\,g\,n^2}{9}\right )}{2\,e}\right )+{\ln \left (c\,{\left (d+e\,x\right )}^n\right )}^2\,\left (\frac {b\,g\,x^3}{3}+\frac {b\,d^3\,g}{3\,e^3}\right )-x\,\left (\frac {d\,\left (\frac {d\,\left (3\,a\,f-b\,g\,n^2\right )}{3\,e}-\frac {d\,\left (a\,f-\frac {a\,g\,n}{3}-\frac {b\,f\,n}{3}+\frac {2\,b\,g\,n^2}{9}\right )}{e}\right )}{e}-\frac {2\,b\,d^2\,g\,n^2}{3\,e^2}\right )+x^3\,\left (\frac {a\,f}{3}-\frac {a\,g\,n}{9}-\frac {b\,f\,n}{9}+\frac {2\,b\,g\,n^2}{27}\right )+\frac {\ln \left (d+e\,x\right )\,\left (3\,a\,d^3\,g\,n+3\,b\,d^3\,f\,n-11\,b\,d^3\,g\,n^2\right )}{9\,e^3} \]
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